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did they told you that hr will contact you after 4 rounds or something else , i got interviewed too and they told me that , i need to know ,it will be really helpful for me if you could tell me what they said. thanks Less
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Nope. no sign at all. In another company interview, met another guy who attended interview at aryaka networks on the 3rd june. He told me same answer :D. you better search for another job, i did like that and got selected to another company, don't just wait for that. If you want confirm, u can ask HR through linkedin (if you remember HR name). or paste your mail id il send the HR linkedin link. Less
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Topic they asked me was distance education vs college education, they will check grammar not accent. No matter how strong your technical skills are, they will allow to 2nd round oly if you clear GD. be prepared. Best company as for fresher. I had 4 rounds- gd, face to face ( hr kind), and then 2 technical rounds. one of my friend had another technical round, totally5 rounds. So final point, they need technical strong guys...i mean it. In Interview they will ask you everythin regarding network(do read wan optimization too), check interviews question which i posted. As your ccnp certified it would be piece of cake for you. do drop mail if need any other info. three of my frnds attended that so have clear idea on interview process. all de best Less
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3. convert the sentence to the modified pig-latin/goat-latin language. Complexity Time: O(n) + O(5) + O(k(k+1)/2) Considering total n characters in sentence. m characters/word O(n): Reading compelete sentence O(2): For vowel. Append ma O(3): For consonant. Append ma and 1st character 1+2+3+... k words = k(k+1)/2 Space: O(n) + 2O(m) + O(5) O(5): unordered_set of vowels 2O(m): Storing 2 word O(n): Storing complete sentence Code #include #include #include void AppendA(std::string& strWord, int& count){ int i = 0; strWord += "ma"; while(i++ us = {'a','e','i','o','u'}; //1st Letter is Vowel if (us.find(std::tolower(strParsed.at(0))) != us.end()) { strWord = strParsed; AppendA(strWord, ++count); } else //consonant { strWord = strParsed.substr(1,strParsed.size()); strWord += strParsed[0]; AppendA(strWord, ++count); } } int main(){ std::string strInput = "Adam wants to go to the university"; std::string strOutput, strWord, strParsed; int count = 0; for (auto& i:strInput){ if (i == ' '){ Process(strParsed, strWord, count); strOutput += strWord + ' '; strWord = ""; strParsed = ""; } else //Store word in strParsed { strParsed += i; } } Process(strParsed, strWord, count); strOutput += strWord ; std::cout<<"Converted string="< Less
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1. You receive a vector/ array and 2 numbers, eg 2 and 5. Between those 2 positions in the vector (2 and 5) you have to reverse the order of the elements. Code #include #include #include using vec = std::vector; using itr = std::vector::iterator; int main(){ vec v = {1,2,9,8,4,5,23,5,252,445,677,5}; //Find position of 2 itr it1 = std::find(v.begin(), v.end(), 2); //O(n) //Find position of 5 itr it2 = std::find(v.begin(), v.end(), 5); //O(n) std::reverse(it1+1, it2); //O(n) for (auto i:v) std::cout< Less
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2. Count words and output top n Complexity n: number of words Space map=O(n), priority_queue = O(k). Since we only create queue of size=k, output vector = O(k) Time Creation of map=O(n), Creation of priority Queue=O(n), Creation of output vector=O(k) Code #include #include #include #include using VS = std::vector; using mypair = std::pair; class Solution { public: VS topKFrequent(VS& vsWords, int k) { VS vsOut; std::priority_queue pq; std::unordered_map um; // for(const auto i : vsWords) //1 um[i]++; //um[key]=value; //um[i] = um[i]+1 for(const auto i:um){ //2 pq.push(make_pair(-i.second,i.first)); if (pq.size() > k) pq.pop(); } while(not pq.empty()){ //3 vsOut.push_back(pq.top().second); pq.pop(); } for(int i = 0; i < vsOut.size()/2; i++) //4 std::swap(vsOut[i], vsOut[vsOut.size()-i - 1]); return vsOut; } }; Less
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There was no one answer for this, and since I didn't know much about vpns, the interviewer guided me through the possible answers! Less
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Hello, Can anyone tell me the best link to study troubleshooting scenarios from?
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#sh vlan brief
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It disables redundant paths and only leaves one broadcast path in a mesh network. It then enables a previous blocked path if one of the primary links becomes disconnected. This creates a network that won't cause broadcast storms but still provide redundancy. Less
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STP operates at the Data Link layer of the OSI model which prevents traffic loops. STP chooses only one root switch/bridge, out of which all data paths span out logically getting the data to the target the quickest and detect and correct link failures when a switch/bridge fails...STP stands for Spanning Tree Protocol. The root is chosen based on its BID( Bridge ID) which is the combination of a 2 byte priority field and the bridge/switch MAC address....Since all switch/bridges on the network start out with the same priority, the one with the lowest MAC address becomes the root bridge. Less
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STP is basically used for loop prevention and to prodive redundancy. Devices participating in STP perform a root bridge election process. Device having the lowest priority will be choosen as the root bridge. If every device participating in STP have the same priority value, device with the lowest mac-address becomes the root bridge. The root bridge will be responsible to make th overall traffic flow decision on the LAN. Non-root bridges use a lowest cost path to reach the root bridge. This cost is dependent on the interface speed. Topological changes downstream from the root bridge is communicated to the root bridge. Less
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I think it is 2^16*2^16 = 2^32. Even though the port number field is 16-bits, a connection is a pair of ports, that should result in 2^32. Less
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Hi Poster, May I know what other questions where asked during your interview? Anything would greatly help. My email is operationstealth@hotmail.com... Thanks! Less
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Agree with KK , a connection is a pair of s.port and d.port - Hence total TCP connections possible are 2^32 on each host. Less
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The key in these questions is to cover the fundamentals, and be ready for the back-and-forth with the interviewer. Might be worth doing a mock interview with one of the Facebook or ex-Facebook Network Engineer experts on Prepfully? They give real-world practice and guidance, which is pretty helpful. prepfully.com/practice-interviews Less
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Can you share some details around system design ? Was it realted to bringing up a new data center or discussion about your previous projects ? Less
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Practice 50-100 LC Easy to Med questions. Should put you on the track to success. Networking - Read CCNP guides for OSPF and BGP. Expect questions in depth and very specific. Less
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I did well.
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Basic String manipulatiob
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Could you please tell me what kind of questions faced in a coding interview ? Please let me know as earliest as possible. Less